What is the sum from n=1 to infinity of 8-6(0.8)^n ?

The sum from n=1 to infinity of 8-6(0.8)^n is diverges

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sum from n=1 to infinity of 8-6(0.8)^n

n = 1 \sum \infty 8 - 6 (0.8)^{n}

diverges

Solution steps

n = 1 \sum \infty 8 - 6 \cdot 0. 8^{n}

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty \frac{1}{2 n ^{2} + n}

n = 2 \sum \infty n e^{- 5 n^{2}}

n = - 3 \sum \infty \frac{1}{3 ^{n + 1}}

n = 3 \sum \infty n e^{- n^{2}}

n = 1 \sum \infty sin (n^{n})

What is the sum from n=1 to infinity of 8-6(0.8)^n ?
The sum from n=1 to infinity of 8-6(0.8)^n is diverges