What is the sum from n=1 to infinity of 1/(6n-1) ?

The sum from n=1 to infinity of 1/(6n-1) is diverges

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sum from n=1 to infinity of 1/(6n-1)

n = 1 \sum \infty \frac{1}{6 n - 1}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{6 n - 1}

Apply Series Comparison Test:

diverges

= diverges

n = 1 \sum \infty \frac{n ^{4}}{6 ^{n}}

k = 0 \sum \infty (- \frac{1}{9})^{k}

n = 1 \sum \infty \frac{6}{n ^{2}}

x = 2 \sum \infty \frac{1}{x} - \frac{1}{x - 1}

k = 2 \sum \infty \frac{1}{( k - 1 ) ^{4}}

What is the sum from n=1 to infinity of 1/(6n-1) ?
The sum from n=1 to infinity of 1/(6n-1) is diverges