What is the sum from n=1 to infinity of n/(1+n) ?

The sum from n=1 to infinity of n/(1+n) is diverges

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sum from n=1 to infinity of n/(1+n)

n = 1 \sum \infty \frac{n}{1 + n}

diverges

Solution steps

n = 1 \sum \infty \frac{n}{1 + n}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty (- \frac{4}{5})^{n}

x = 0 \sum \infty \frac{1}{x}

n = 1 \sum \infty (0.8)^{n - 1}

n = 0 \sum \infty 3 (\frac{3}{4})^{n}

n = 1 \sum \infty \frac{2 n + 1}{n + 2}

What is the sum from n=1 to infinity of n/(1+n) ?
The sum from n=1 to infinity of n/(1+n) is diverges