What is the sum from n=1 to infinity of (11^n)/(n+1) ?

The sum from n=1 to infinity of (11^n)/(n+1) is diverges

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sum from n=1 to infinity of (11^n)/(n+1)

n = 1 \sum \infty \frac{1 1 ^{n}}{n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{1 1 ^{n}}{n + 1}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty \frac{n}{ln ( n + 1 )}

n = 1 \sum \infty \frac{1}{n n}

n = 0 \sum \infty - n^{2}

n = 0 \sum \infty 9 e^{- 9 n}

n = 0 \sum \infty 10 (\frac{3}{4})^{n}

What is the sum from n=1 to infinity of (11^n)/(n+1) ?
The sum from n=1 to infinity of (11^n)/(n+1) is diverges