What is the solution for (dy}{dx}=\frac{(1-2x))/y ?

The solution for (dy}{dx}=\frac{(1-2x))/y is y=sqrt(2x-2x^2+c_{1)},y=-sqrt(2x-2x^2+c_{1)}

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(dy}{dx}=\frac{(1-2x))/y

\frac{d y}{d x} = \frac{( 1 - 2 x )}{y}

y = 2 x - 2 x^{2} + c_{1}, y = - 2 x - 2 x^{2} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{( 1 - 2 x )}{y}

Solve separable ODE:

y = 2 x - 2 x^{2} + c_{1}, y = - 2 x - 2 x^{2} + c_{1}

y = 2 x - 2 x^{2} + c_{1}, y = - 2 x - 2 x^{2} + c_{1}

\frac{1}{t} y^{^{'}} = 6 sin^{2} (y), y (1) = \frac{5 π}{4}

y^{^{'}} = \frac{y \cdot cos ( x )}{1 - 2 y}

y^{^{'}} = \frac{x}{y}, y (1) = 0

y^{^{'}} x ln (x) - y = 0, y (2) = ln (4)

y^{^{'}} + y tan (x) = 0

What is the solution for (dy}{dx}=\frac{(1-2x))/y ?
The solution for (dy}{dx}=\frac{(1-2x))/y is y=sqrt(2x-2x^2+c_{1)},y=-sqrt(2x-2x^2+c_{1)}