y^'-y=2

Lösung

y^{^{'}} - y = 2

y = e^{t + c_{1}} - 2

Schritte zur Lösung

y^{'} (t) - y = 2

Solve separable ODE:

y = e^{t + c_{1}} - 2

y = e^{t + c_{1}} - 2

(3 x^{2} + 2)^{3} y^{^{'}} - x y^{2} = 0, y (0) = \frac{3}{2}

\frac{d r}{d t} = 0.1872 r

x tan (x) d x - y cos (x) d y = 0

\frac{d y}{d x} = \frac{x y}{x + 1}

\frac{d y}{d t} = y t^{3} - 1.5 y