y^3dy=xdx

Lösung

y^{3} d y = x d x

y = 4 2 x^{2} + c_{1}, y = - 4 2 x^{2} + c_{1}

Schritte zur Lösung

y^{3} d y = x d x

Solve separable ODE:

y = 4 2 x^{2} + c_{1}, y = - 4 2 x^{2} + c_{1}

y = 4 2 x^{2} + c_{1}, y = - 4 2 x^{2} + c_{1}

x^{2} y - x y^{^{'}} + y = 0

y^{^{'}} + \frac{1}{2 t y} = 0

\frac{d y}{d x} = x^{2} y + y

2 y e^{y^{2}} y^{^{'}} = 2 x + 3 x

1 - x^{2} d y - x y d x = 0