y^'+2y=6

Lösung

y^{^{'}} + 2 y = 6

y = - e^{- 2 t - c_{1}} + 3

Schritte zur Lösung

y^{'} (t) + 2 y = 6

Solve separable ODE:

y = - e^{- 2 t - c_{1}} + 3

y = - e^{- 2 t - c_{1}} + 3

x^{2} y^{3} y^{^{'}} = 2 x^{3} y

\frac{d y}{d x} = 8 x (y^{2} + 1)

\frac{d y}{d t} = 6 y t^{2}

x^{^{'}} - a x = 0

\frac{d y}{d t} + 2 y = 6, y (0) = 0