y^'+14xy=0

Lösung

y^{^{'}} + 14 x y = 0

y = e^{- 7 x^{2} + c_{1}}

Schritte zur Lösung

y^{'} (x) + 14 x y = 0

Solve separable ODE:

y = e^{- 7 x^{2} + c_{1}}

y = e^{- 7 x^{2} + c_{1}}

y y^{^{'}} e^{y^{2}} = x - 1

y^{^{'}} = - y cos (x)

y^{^{'}} - 2 t y^{3} = 0, y (2) = 1

y^{^{'}} = \frac{7 y}{x}

\frac{d y}{d x} = \frac{x 1 - y ^{2}}{y 2 x ^{2} + 1}