y^'=ysec(x)

Lösung

y^{^{'}} = y sec (x)

y = e^{c_{1}} tan (x) + e^{c_{1}} sec (x)

Schritte zur Lösung

y^{'} (x) = y sec (x)

Solve separable ODE:

y = e^{c_{1}} tan (x) + e^{c_{1}} sec (x)

y = e^{c_{1}} tan (x) + e^{c_{1}} sec (x)

\frac{d y}{d x} = y + \frac{y}{x ln ( x )}

\frac{d y}{d t} + 20 y = 24, y = \frac{6}{5} - \frac{6}{5} e^{- 20 t}

d y = 1 - 4 y^{2} d x

y^{^{'}} = cos (x) tan (y)

y e^{y} d y + x d x = 0