xy^'=1-y

Lösung

x y^{^{'}} = 1 - y

y = - \frac{c _{1}}{x} + 1

Schritte zur Lösung

x y^{'} (x) = 1 - y

Solve separable ODE:

y = - \frac{c _{1}}{x} + 1

y = - \frac{c _{1}}{x} + 1

(\frac{d ^{2} x}{d x ^{2}} + 4 \frac{d y}{d x} + 20 y)^{2} = 0

\frac{d p}{d t} = 5 p - p^{2}

y^{^{'}} + 3 x y = 0

y^{^{'}} = - y + 2

y^{^{'}} = (x + 1) y