y^'=-y+2

Lösung

y^{^{'}} = - y + 2

y = e^{- t - c_{1}} + 2

Schritte zur Lösung

y^{'} (t) = - y + 2

Solve separable ODE:

y = e^{- t - c_{1}} + 2

y = e^{- t - c_{1}} + 2

y^{^{'}} = (x + 1) y

5 y^{4} \frac{d y}{d x} = 4 x

y^{^{'}} - x^{3} y^{2} = 4 x^{3}

\frac{d y}{d t} = y t^{2} - 1.1 y

\frac{d y}{d x} = \frac{2 x}{3 y} e^{x^{2} - 3 y^{2}}, y (1) = - 1