y^'-9x^2y+y=0

Lösung

y^{^{'}} - 9 x^{2} y + y = 0

y = e^{3 x^{3} - x + c_{1}}

Schritte zur Lösung

y^{'} (x) - 9 x^{2} y + y = 0

Solve separable ODE:

y = e^{3 x^{3} - x + c_{1}}

y = e^{3 x^{3} - x + c_{1}}

y^{^{'}} = x (y - 1) - 2 y + 2

y^{^{'}} = \frac{y ^{3}}{x ^{2}}

y^{^{'}} - 6 x y = 0

y^{^{'}} + y \cdot cos (t) = - cos (t)

\frac{d y}{d x} = (x^{2} - 7) y^{2}