2xe^{2t}dt+(1+e^{2t})dx=0

Lösung

2 x e^{2 t} d t + (1 + e^{2 t}) d x = 0

t = \frac{ln ( \frac{c _{1}}{x} - 1 )}{2}

Schritte zur Lösung

2 x e^{2 t} d t + (1 + e^{2 t}) d x = 0

Solve separable ODE:

t = \frac{ln ( \frac{c _{1}}{x} - 1 )}{2}

t = \frac{ln ( \frac{c _{1}}{x} - 1 )}{2}

x^{^{'}} + a x = 0

y^{^{'}} x ln (x) - y = 0

y^{^{'}} = \frac{3}{x} (y - y^{\frac{2}{3}})

u^{^{'}} = 5 e^{8 x - H (x)}

y^{^{'}} = 9 y