2(x-1)y^'=y

Lösung

2 (x - 1) y^{^{'}} = y

y = c_{1} x - 1

Schritte zur Lösung

2 (x - 1) y^{'} (x) = y

Solve separable ODE:

y = c_{1} x - 1

y = c_{1} x - 1

(x^{3} + 1) y^{^{'}} - 3 x^{2} y = 0

\frac{d y}{d x} = 3 y, y (0) = 5.2

x y^{^{'}} - 3 y = - 3

a y^{2} + \frac{d y}{d x} = 0

\frac{d y}{d t} + 4 y = 11, y (0) = 1