y^'=(1+y^2)cos(t)

Lösung

y^{^{'}} = (1 + y^{2}) cos (t)

y = tan (sin (t) + c_{1})

Schritte zur Lösung

y^{'} (t) = (1 + y^{2}) cos (t)

Solve separable ODE:

y = tan (sin (t) + c_{1})

y = tan (sin (t) + c_{1})

x y^{2} y^{^{'}} = x + 10

\frac{d y}{d x} = \frac{3 e ^{x}}{y}

y^{2} y^{^{'}} = x - 2

\frac{d y}{d x} - \frac{2}{x} y - \frac{1}{x y} = 0

\frac{d y}{d t} = 0.1 y, y (0) = 600, t = 5