(1-x)y^'=6y

Lösung

(1 - x) y^{^{'}} = 6 y

y = \frac{c _{1}}{1 - 6 x + 15 x ^{2} - 20 x ^{3} + 15 x ^{4} - 6 x ^{5} + x ^{6}}

Schritte zur Lösung

(1 - x) y^{'} (x) = 6 y

Solve separable ODE:

y = \frac{c _{1}}{1 - 6 x + 15 x ^{2} - 20 x ^{3} + 15 x ^{4} - 6 x ^{5} + x ^{6}}

y = \frac{c _{1}}{1 - 6 x + 15 x ^{2} - 20 x ^{3} + 15 x ^{4} - 6 x ^{5} + x ^{6}}

x y^{2} d y + (x^{2} + 1) d x = 0

\frac{d y}{x - 1} = y d x

t \frac{d y}{d t} = 17 y

\frac{d y}{d x} = (y - 2)^{4}

sin (x) d x + \frac{d y}{y} = 0