y^'-9y=0

Lösung

y^{^{'}} - 9 y = 0

y = e^{9 t + c_{1}}

Schritte zur Lösung

y^{'} (t) - 9 y = 0

Solve separable ODE:

y = e^{9 t + c_{1}}

y = e^{9 t + c_{1}}

5 y^{4} \frac{d y}{d x} = 2 x

y^{^{'}} + y = \frac{y}{x}

\frac{d y}{d x} = a - b \cdot y

\frac{d y}{d x} - 3 y = 12

(1 + y) y^{^{'}} = y