y^'+y/6 =2,y(-1)=0

Lösung

y^{^{'}} + \frac{y}{6} = 2, y (- 1) = 0

y = - 12 e^{\frac{- t - 1}{6}} + 12

Schritte zur Lösung

y^{'} (t) + \frac{y}{6} = 2

Solve separable ODE:

y = - 12 e^{\frac{- t - 1}{6}} + 12

y = - 12 e^{\frac{- t - 1}{6}} + 12

x \frac{d y}{d x} = (1 + y)^{2}

\frac{d y}{d x} = \frac{e ^{x} - cos ( 2 x )}{y}

y^{^{'}} = - 1 - 2 y

\frac{d y}{d x} = 7 y^{2} x^{3}

3 y^{2} \frac{d y}{d x} = 2 x