(dy)/(dx)=y^2+4y+10

Lösung

\frac{d y}{d x} = y^{2} + 4 y + 10

y = tan (6 (x + c_{1})) 6 - 2

Schritte zur Lösung

\frac{d y}{d x} = y^{2} + 4 y + 10

Solve separable ODE:

y = tan (6 (x + c_{1})) 6 - 2

y = tan (6 (x + c_{1})) 6 - 2

y^{^{'}} - 20 x y = 0

\frac{d y}{d x} = x y + 3 x - y - 3

y^{^{'}} = 4 x^{3} y^{2}

y^{^{'}} = \frac{1 - 6 x ^{2}}{2 y + 3}

y^{^{'}} = - ln ∣ x ∣ y