(y^')/x+y=1

Lösung

\frac{y ^{^{'}}}{x} + y = 1

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 1

Schritte zur Lösung

\frac{y ^{'} ( x )}{x} + y = 1

Solve separable ODE:

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 1

y = - e^{- \frac{x ^{2}}{2} - c_{1}} + 1

sin (y) + \frac{1}{2} x cos (y) \frac{d y}{d x} = 3

y^{^{'}} = e^{x} e^{- y}

\frac{d P}{d t} = 4 Pt, P (1) = 5

(1 - x^{2}) \frac{d y}{d x} + x y = x

\frac{d y}{d x} = e^{x} sin (y)