y^'+x^3y=0

Lösung

y^{^{'}} + x^{3} y = 0

y = e^{- \frac{x ^{4}}{4} + c_{1}}

Schritte zur Lösung

y^{'} (x) + x^{3} y = 0

Solve separable ODE:

y = e^{- \frac{x ^{4}}{4} + c_{1}}

y = e^{- \frac{x ^{4}}{4} + c_{1}}

\frac{d y}{d t} = y

\frac{d h}{d t} = - \frac{3}{100} \cdot h - 18

\frac{d y}{d x} - e^{- y} sec^{2} (x) = 0

y^{^{'}} - 14 x y = 0

\frac{d y}{d x} + x y = 2 x