y^'=4xy^2

Lösung

y^{^{'}} = 4 x y^{2}

y = - \frac{1}{2 x ^{2} + c _{1}}

Schritte zur Lösung

y^{'} (x) = 4 x y^{2}

Solve separable ODE:

y = - \frac{1}{2 x ^{2} + c _{1}}

y = - \frac{1}{2 x ^{2} + c _{1}}

\frac{d y}{d x} - 3 x^{2} y = 0

\frac{d y}{d x} = x e^{y - x^{2}}

y^{^{'}} + t y = y

x^{2} \frac{d y}{d x} + x y - y = 0

u^{^{'}} = csc (H (x)) cos (\frac{x}{2})