x^'=(2x)/(t+1)

Lösung

x^{^{'}} = \frac{2 x}{t + 1}

x = e^{c_{1}} t^{2} + 2 e^{c_{1}} t + e^{c_{1}}

Schritte zur Lösung

x^{'} (t) = \frac{2 x}{t + 1}

Solve separable ODE:

x = e^{c_{1}} t^{2} + 2 e^{c_{1}} t + e^{c_{1}}

x = e^{c_{1}} t^{2} + 2 e^{c_{1}} t + e^{c_{1}}

y^{^{'}} + (x + 9) y = 0

\frac{d y}{d t} = - a y

\frac{d P}{d t} = 4 Pt, P (1) = 2

\frac{d y}{d t} = (t y)

\frac{d y}{d x} = y - 4