y-y^'=0

Lösung

y - y^{^{'}} = 0

y = e^{t + c_{1}}

Schritte zur Lösung

y - y^{'} (t) = 0

Solve separable ODE:

y = e^{t + c_{1}}

y = e^{t + c_{1}}

\frac{d y}{d x} = 4 y - y^{2}

\frac{d y}{d x} = 9 x y

y y^{^{'}} = (y^{2} + 1) sin (x)

y^{^{'}} = \frac{2 y}{x + 4 x ^{3}}

y + x y^{^{'}} = 0