(y-1)dx+(x+3)dy=0

Lösung

(y - 1) d x + (x + 3) d y = 0

y = \frac{c _{1}}{x + 3} + 1

Schritte zur Lösung

(y - 1) d x + (x + 3) d y = 0

Solve separable ODE:

y = \frac{c _{1}}{x + 3} + 1

y = \frac{c _{1}}{x + 3} + 1

y^{^{'}} = 5 y - 15

y = arcsin (2 x^{3}) y^{^{'}}

2 f (t) + 2 f^{^{'}} (t) = 1

x y - y \frac{d y}{d x} = 2 x, y (- 1) = 3

y^{^{'}} = \frac{8 y}{x}