y^'=-3y^{4/3}sin(t)

Lösung

y^{^{'}} = - 3 y^{\frac{4}{3}} sin (t)

y = - \frac{27}{27 cos ^{3} ( t ) + 27 c _{1} cos ^{2} ( t ) + 9 c _{1}^{2} cos ( t ) + c _{1}^{3}}

Schritte zur Lösung

y^{'} (t) = - 3 y^{\frac{4}{3}} sin (t)

Solve separable ODE:

y = - \frac{27}{27 cos ^{3} ( t ) + 27 c _{1} cos ^{2} ( t ) + 9 c _{1}^{2} cos ( t ) + c _{1}^{3}}

y = - \frac{27}{27 cos ^{3} ( t ) + 27 c _{1} cos ^{2} ( t ) + 9 c _{1}^{2} cos ( t ) + c _{1}^{3}}

\frac{d y}{d x} = \frac{x + 1}{e ^{y}}

\frac{d y}{d x} = - \frac{8}{9} x^{2} y^{6}

y^{^{'}} = (\frac{2}{x} - x) y

x^{5} \frac{d y}{d x} = 3 x^{2} 1 - y^{2}

x^{3} + 8 y \frac{d y}{d x} = 0