(\partial)/(\partial x)(sin(2x+y)sin(y))

Lösung

\frac{\partial}{\partial x} (sin (2 x + y) sin (y))

sin (y) cos (2 x + y) \cdot 2

Schritte zur Lösung

\frac{\partial}{\partial x} (sin (2 x + y) sin (y))

Behandle

y

als Konstante

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (y) \frac{\partial}{\partial x} (sin (2 x + y))

Wende die Kettenregel an:

cos (2 x + y) \frac{\partial}{\partial x} (2 x + y)

= cos (2 x + y) \frac{\partial}{\partial x} (2 x + y)

\frac{\partial}{\partial x} (2 x + y) = 2

= sin (y) cos (2 x + y) \cdot 2

\int (x + 3) (x^{2} + 6 x + 7)^{6} d x

\int \frac{sin ( 9 ln ( t ) )}{t} d t

d er i v a t i v e y = cos ((π x)^{8})

t an g e n t y = 3 e^{x} cos (x), (0, 3)

4 y^{^{''}} + 12 y^{^{'}} + 9 y = 0