y*y^'-2x=sin(x)

Lösung

y \cdot y^{^{'}} - 2 x = sin (x)

y = - 2 cos (x) + 2 x^{2} + c_{1}, y = - - 2 cos (x) + 2 x^{2} + c_{1}

Schritte zur Lösung

y \cdot y^{'} (x) - 2 x = sin (x)

Solve separable ODE:

y = - 2 cos (x) + 2 x^{2} + c_{1}, y = - - 2 cos (x) + 2 x^{2} + c_{1}

y = - 2 cos (x) + 2 x^{2} + c_{1}, y = - - 2 cos (x) + 2 x^{2} + c_{1}

\frac{d y}{d x} = 0.125 (y - 3), y (0) = 5

e^{x} \frac{d y}{d x} - sec (y) - x sec (y) = 0

2 y y^{^{'}} + 1 = e^{x - 1}

y^{^{'}} = 8 y - 5

\frac{d y}{d t} = (2 y + 1)