y^'=(y+2)^2

Lösung

y^{^{'}} = (y + 2)^{2}

y = - \frac{1}{t + c _{1}} - \frac{2 t}{t + c _{1}} - \frac{2 c _{1}}{t + c _{1}}

Schritte zur Lösung

y^{'} (t) = (y + 2)^{2}

Solve separable ODE:

y = - \frac{1}{t + c _{1}} - \frac{2 t}{t + c _{1}} - \frac{2 c _{1}}{t + c _{1}}

y = - \frac{1}{t + c _{1}} - \frac{2 t}{t + c _{1}} - \frac{2 c _{1}}{t + c _{1}}

\frac{d y}{d x} = 12 x y - 2 x

y^{^{'}} = (\frac{x}{y}) (\frac{y ^{2} + 1}{x ^{2} - 1})

\frac{d y}{d x} + 9 x e^{y} = 0

\frac{d x}{d t} + \frac{x}{100} = 75, x (0) = 5000

y^{^{'}} = - 4 x^{5} e^{y}