2y+3+(2x-5)(dy)/(dx)=0

Lösung

2 y + 3 + (2 x - 5) \frac{d y}{d x} = 0

y = \frac{c _{1}}{2 ( 2 x - 5 )} - \frac{3}{2}

Schritte zur Lösung

2 y + 3 + (2 x - 5) \frac{d y}{d x} = 0

Solve separable ODE:

y = \frac{c _{1}}{2 ( 2 x - 5 )} - \frac{3}{2}

y = \frac{c _{1}}{2 ( 2 x - 5 )} - \frac{3}{2}

\frac{d y}{d x} + \frac{y}{x} = 0

y^{^{'}} = \frac{6 x - 3}{y}

y^{^{'}} = \frac{x}{y e ^{y + x^{2}}}

(x y)^{2} y^{^{'}} = \frac{x + 5}{y}

y^{^{'}} = \frac{x}{y - 1}