y^'=(x^2)/(-4y)

Lösung

y^{^{'}} = \frac{x ^{2}}{- 4 y}

y = - \frac{x ^{3}}{6} + c_{1}, y = - - \frac{x ^{3}}{6} + c_{1}

Schritte zur Lösung

y^{'} (x) = \frac{x ^{2}}{- 4 y}

Solve separable ODE:

y = - \frac{x ^{3}}{6} + c_{1}, y = - - \frac{x ^{3}}{6} + c_{1}

y = - \frac{x ^{3}}{6} + c_{1}, y = - - \frac{x ^{3}}{6} + c_{1}

y^{^{'}} = \frac{( 3 x ^{2} - 1 )}{( 3 + 2 y )}, y (1) = 1

\frac{d}{d x} (sin (y)) = x

y^{^{'}} - y = y^{3}

d y = (y x^{2} - 1.1 y) d x

\frac{d y}{d x} = 6 - 3 y