y^'=(e^{2x})/(4y^3)

Lösung

y^{^{'}} = \frac{e ^{2 x}}{4 y ^{3}}

y = 4 \frac{e ^{2 x} + c _{1}}{2}, y = - 4 \frac{e ^{2 x} + c _{1}}{2}

Schritte zur Lösung

y^{'} (x) = \frac{e ^{2 x}}{4 y ^{3}}

Solve separable ODE:

y = 4 \frac{e ^{2 x} + c _{1}}{2}, y = - 4 \frac{e ^{2 x} + c _{1}}{2}

y = 4 \frac{e ^{2 x} + c _{1}}{2}, y = - 4 \frac{e ^{2 x} + c _{1}}{2}

(x + 1) (y - 1) d x + (x - 1) (y + 1) d y = 0

(1 + 2 y) x d x + (1 + x^{2}) d y = 0

\frac{d y}{d x} = e^{(x + y)}

x y^{^{'}} - y = 1

y y^{^{'}} = x^{2} + x, y (13) = 20