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Beliebt Rechnen >

(yln(x))y^'=(y^2+1)/x

Lösung

(y ln (x)) y^{^{'}} = \frac{y ^{2} + 1}{x}

Lösung

y = c_{1} ln^{2} (x) - 1, y = - c_{1} ln^{2} (x) - 1

Schritte zur Lösung

(y ln (x)) y^{'} (x) = \frac{y ^{2} + 1}{x}

Solve separable ODE:

y = c_{1} ln^{2} (x) - 1, y = - c_{1} ln^{2} (x) - 1

y = c_{1} ln^{2} (x) - 1, y = - c_{1} ln^{2} (x) - 1

Graph

Beliebte Beispiele

(dy}{dx}=\frac{xsin(x))/y ,y(0)=-7

\frac{d y}{d x} = \frac{x sin ( x )}{y}, y (0) = - 7

(dx)/(dt)=x^2+1/25 ,x(0)=-3

\frac{d x}{d t} = x^{2} + \frac{1}{25}, x (0) = - 3

y = (x + 1) y^{^{'}} - 1

e^yy^'=((ln(t))^2)/t ,y(1)=ln(4)

e^{y} y^{^{'}} = \frac{( ln ( t ) ) ^{2}}{t}, y (1) = ln (4)

(y^2-1)dx+xdy=0

(y^{2} - 1) d x + x d y = 0