(y^2-y)dx+xdy=0

Lösung

(y^{2} - y) d x + x d y = 0

y = - \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

Schritte zur Lösung

(y^{2} - y) d x + x d y = 0

Solve separable ODE:

y = - \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

y = - \frac{e ^{c_{1}} x}{1 - e ^{c_{1}} x}

y y^{^{'}} = x^{2} e^{2 x + 2 y} sin (3 x)

x \cdot \frac{d y}{d x} = 2 + 3 y

5 y d x = 3 x d y

\frac{d x}{d k} + a x (k) = b

y^{^{'}} - \frac{cos ( x )}{e ^{y}} = 0