xy^'=3(y^2+y)

Lösung

x y^{^{'}} = 3 (y^{2} + y)

y = \frac{e ^{c_{1}} x ^{3}}{1 - e ^{c_{1}} x ^{3}}

Schritte zur Lösung

x y^{'} (x) = 3 (y^{2} + y)

Solve separable ODE:

y = \frac{e ^{c_{1}} x ^{3}}{1 - e ^{c_{1}} x ^{3}}

y = \frac{e ^{c_{1}} x ^{3}}{1 - e ^{c_{1}} x ^{3}}

y^{^{'}} = x y, y (1) = 1

\frac{d v}{d t} + \frac{v}{3} = 4

\frac{5}{3} y + \frac{d y}{d x} = 3 - 5 y

y^{^{'}} = 4 y^{2} cos (x)

\frac{y ^{^{'}}}{x} = - 2 y