3y^'=ycos(3x),y(0)=1

Lösung

3 y^{^{'}} = y cos (3 x), y (0) = 1

y = e^{\frac{s i n ( 3 x )}{9}}

Schritte zur Lösung

3 y^{'} (x) = y cos (3 x)

Solve separable ODE:

y = e^{\frac{s i n ( 3 x )}{9}}

y = e^{\frac{s i n ( 3 x )}{9}}

2 y y^{^{'}} = 2 x^{3} - 1

\frac{d y}{d x} = k x y

d y = e^{3 x - 2 y} d x

\frac{d y}{d x} = e^{3 x} e^{2 y}

y \frac{p d p}{d y} - (p)^{2} + p = 0