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Beliebt Rechnen >

16yy^'+9x=0

Lösung

16 y y^{^{'}} + 9 x = 0

Lösung

y = \frac{- 9 x ^{2} + c _{1}}{4}, y = - \frac{- 9 x ^{2} + c _{1}}{4}

Schritte zur Lösung

16 y y^{'} (x) + 9 x = 0

Solve separable ODE:

y = \frac{- 9 x ^{2} + c _{1}}{4}, y = - \frac{- 9 x ^{2} + c _{1}}{4}

y = \frac{- 9 x ^{2} + c _{1}}{4}, y = - \frac{- 9 x ^{2} + c _{1}}{4}

Graph

Beliebte Beispiele

x y^{^{'}} = y + 1 + x y + x

y^'=(sin(2x))/(cos(3y)),y(0)=1

y^{^{'}} = \frac{sin ( 2 x )}{cos ( 3 y )}, y (0) = 1

y^'(t)=(3+y)(1-y),y(0)=4

y^{^{'}} (t) = (3 + y) (1 - y), y (0) = 4

y^'+y=y(te^{t^2}+1),y(0)=1

y^{^{'}} + y = y (t e^{t^{2}} + 1), y (0) = 1

y^'=(y^2)/(x^3),y(2)=4

y^{^{'}} = \frac{y ^{2}}{x ^{3}}, y (2) = 4