y^'= t/y ,y(0)=1

Lösung

y^{^{'}} = \frac{t}{y}, y (0) = 1

y = t^{2} + 1

Schritte zur Lösung

y^{'} (t) = \frac{t}{y}

Solve separable ODE:

y = t^{2} + 1

y = t^{2} + 1

y^{^{'}} - 10 x y = 0

2 t y^{^{'}} = 6 y

y^{^{'}} = \frac{3 sin ( x )}{sin ( y )}, y (0) = \frac{π}{2}

3 y^{3} d y - 6 x^{4} d x = 0

\frac{d y}{d x} = y (8 x^{2} + 4)