y^'=(6x)/(1+2y),y(6)=0

Lösung

y^{^{'}} = \frac{6 x}{1 + 2 y}, y (6) = 0

y = \frac{- 1 + 12 x ^{2} - 431}{2}

Schritte zur Lösung

y^{'} (x) = \frac{6 x}{1 + 2 y}

Solve separable ODE:

y = \frac{- 1 + 12 x ^{2} - 431}{2}

y = \frac{- 1 + 12 x ^{2} - 431}{2}

y^{^{'}} + 2 y = - 5

3 x^{^{'}} + x = 1

t^{9} \frac{d y}{d t} + 2 t^{8} y = 0

\frac{d y}{d x} = - 1 \cdot \frac{1}{( x + 9 ) ^{2}} \cdot (y + 1)

\frac{d y}{d x} = 4 + y^{2}