y^'=y^2-y

Lösung

y^{^{'}} = y^{2} - y

y = \frac{1}{1 - e ^{t + c_{1}}}

Schritte zur Lösung

y^{'} (t) = y^{2} - y

Solve separable ODE:

y = \frac{1}{1 - e ^{t + c_{1}}}

y = \frac{1}{1 - e ^{t + c_{1}}}

x y^{^{'}} = y + 3

\frac{d}{d x} (y^{2}) = 8 x

(x + 1) \frac{d y}{d x} + 1 = e^{- y}

y^{^{'}} + 4 x y = 4 e^{6} x

\frac{d y}{d t} = - 0.7654 y