(dy)/(dx)2x^3=2y^2+5

Lösung

\frac{d y}{d x} 2 x^{3} = 2 y^{2} + 5

y = \frac{5 tan ( \frac{5 ( 4 c _{1} x ^{2} - 1 )}{2 2 x ^{2}} )}{2}

Schritte zur Lösung

\frac{d y}{d x} 2 x^{3} = 2 y^{2} + 5

Solve separable ODE:

y = \frac{5 tan ( \frac{5 ( 4 c _{1} x ^{2} - 1 )}{2 2 x ^{2}} )}{2}

y = \frac{5 tan ( \frac{5 ( 4 c _{1} x ^{2} - 1 )}{2 2 x ^{2}} )}{2}

\frac{d y}{d x} = (2 x) y

y^{^{'}} = a y + b, y (0) = c

\frac{d y}{d t} = - \frac{y}{100}

y^{^{'}} = - 2.1 (y - 10)

\frac{d r}{4 r} = - t d t