3ydx+3dx=4xdy

Lösung

3 y d x + 3 d x = 4 x d y

y = c_{1} x^{\frac{3}{4}} - 1

Schritte zur Lösung

3 y d x + 3 d x = 4 x d y

Solve separable ODE:

y = c_{1} x^{\frac{3}{4}} - 1

y = c_{1} x^{\frac{3}{4}} - 1

y^{^{'}} + \frac{y}{x} = \frac{2}{x}

y^{3} \frac{d y}{d x} = 4 x^{3} y^{4} - 16 x^{3}

y^{^{'}} = - 0.06 y

\frac{d y}{d x} = \frac{x ^{2} - 1}{y ^{2} - 1}, y (2) = 2

y^{^{'}} = 7 y, y (0) = 1