x+3y^2sqrt(x^2+1)y^'=0

Lösung

x + 3 y^{2} x^{2} + 1 y^{^{'}} = 0

y = 3 - x^{2} + 1 + c_{1}

Schritte zur Lösung

x + 3 y^{2} x^{2} + 1 y^{'} (x) = 0

Solve separable ODE:

y = 3 - x^{2} + 1 + c_{1}

y = 3 - x^{2} + 1 + c_{1}

5 x^{^{'}} + 2 x - 1 = 0

y^{^{'}} = x^{2} \cdot y - 1.1 \cdot y

y^{^{'}} = \frac{3 t ^{2}}{4 + 2 y}, y (0) = - 1

y^{^{'}} = 4 y^{3}

\frac{d y}{d x} = (x^{5} (y - 6)), y (0) = 8