(x^{-2}y^{-5})dx+(x^{-3}y^{-4})dy=0

解答

(x^{- 2} y^{- 5}) d x + (x^{- 3} y^{- 4}) d y = 0

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

求解步骤

(x^{- 2} y^{- 5}) d x + (x^{- 3} y^{- 4}) d y = 0

求解可分离方程:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

\frac{d V}{d t} = 20 - \frac{8}{100} V

\frac{d y}{d t} = \frac{2 t}{1 + 2 y}

\frac{d y}{d x} + y tan (x) = 0

y 1 - x^{2} \cdot y^{^{'}} + 1 - y^{2} = 0

y^{^{'}} = \frac{sin ( 2 x )}{cos ( 3 y )}