y^'+4y=5

Lösung

y^{^{'}} + 4 y = 5

y = - \frac{e ^{- 4 t - c_{1}}}{4} + \frac{5}{4}

Schritte zur Lösung

y^{'} (t) + 4 y = 5

Solve separable ODE:

y = - \frac{e ^{- 4 t - c_{1}}}{4} + \frac{5}{4}

y = - \frac{e ^{- 4 t - c_{1}}}{4} + \frac{5}{4}

y^{^{'}} + 2 y = - 8

\frac{d y}{d x} = - \frac{3}{5} x^{7} y^{3}

\frac{d x}{d y} + 2 x y^{2} = 0

\frac{d v}{d x} = - 0.4 v

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0, y (0) = 5