y^'=(-t)/y

Lösung

y^{^{'}} = \frac{- t}{y}

y = - t^{2} + c_{1}, y = - - t^{2} + c_{1}

Schritte zur Lösung

y^{'} (t) = \frac{- t}{y}

Solve separable ODE:

y = - t^{2} + c_{1}, y = - - t^{2} + c_{1}

y = - t^{2} + c_{1}, y = - - t^{2} + c_{1}

\frac{d y}{d x} = 3 e^{x - y}, y (0) = ln (8)

(1 + x) y^{^{'}} - x y = 0

y^{^{'}} sec (x) = 5 y^{2}

\frac{d y}{d x} = 3 e^{x - y}, y (0) = ln (9)

\frac{d v}{d t} = 1 - 2 v