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Popular >

(dy)/(dt)=te^y

Solution

\frac{d y}{d t} = t e^{y}

Solution

y = - ln (- \frac{t ^{2}}{2} - c_{1})

Solution steps

\frac{d y}{d t} = t e^{y}

Solve separable ODE:

y = - ln (- \frac{t ^{2}}{2} - c_{1})

y = - ln (- \frac{t ^{2}}{2} - c_{1})

Graph

Popular Examples

(dy)/(dx)=y-2y^2

\frac{d y}{d x} = y - 2 y^{2}

y^'=(6yx^2)/(x^3+1)

y^{^{'}} = \frac{6 y x ^{2}}{x ^{3} + 1}

y^'= x/(y^2sqrt(1+x))

y^{^{'}} = \frac{x}{y ^{2} 1 + x}

(dy}{dx}=\frac{6y)/x ,x>0

\frac{d y}{d x} = \frac{6 y}{x}, x > 0

y^'=\sqrt[3]{y/(x-1)}

y^{^{'}} = 3 \frac{y}{x - 1}

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dt)=te^y ?
The solution for (dy)/(dt)=te^y is y=-ln(-(t^2)/2-c_{1})