(y+1)y^'-x^2y-y=0,y(3)=1

Lösung

(y + 1) y^{^{'}} - x^{2} y - y = 0, y (3) = 1

y + ln (y) = \frac{x ^{3}}{3} + x - 11

Schritte zur Lösung

(y + 1) y^{'} (x) - x^{2} y - y = 0

Solve separable ODE:

y + ln (y) = \frac{x ^{3}}{3} + x - 11

y + ln (y) = \frac{x ^{3}}{3} + x - 11

\frac{d y}{d x} = - \frac{7}{8} x^{3} y^{4}

y^{^{'}} + \frac{1}{50} y = 0.2

\frac{d y}{d x} = - \frac{7}{3} x^{5} y^{6}

\frac{d y}{d x} = - k y

y^{^{'}} = - \frac{3 x + 3 x y ^{2}}{y x ^{2} + 2 y}