y^'=(10x+3)(7y+2)

Lösung

y^{^{'}} = (10 x + 3) (7 y + 2)

y = \frac{e ^{35 x^{2} + 21 x + c_{1}}}{7} - \frac{2}{7}

Schritte zur Lösung

y^{'} (x) = (10 x + 3) (7 y + 2)

Solve separable ODE:

y = \frac{e ^{35 x^{2} + 21 x + c_{1}}}{7} - \frac{2}{7}

y = \frac{e ^{35 x^{2} + 21 x + c_{1}}}{7} - \frac{2}{7}

x^{^{'}} + x = - 2

\frac{d y}{d x} = y (2 x + 1), y (0) = 2

\frac{d y}{d x} = (y + 1) x^{3}

\frac{d y}{d x} = 4 (y^{2} + 1), x (\frac{π}{4}) = 1

2 x \frac{d y}{d x} = (2 x + 1) y